45. The rules for determining how much the motion of each body is changed because of the collision of other bodies
Collisions with other bodies cause bodies to:
- increase or decrease their motions, or
- turn elsewhere
In order to calculate such changes, we only need to:
- subtract the amount of force in each, either to move or to resist motion, and
- establish for certain that which is stronger always achieves its effect.
This could easily be deduced by calculation if:
- only 2 bodies encountered each other mutually
- they were perfectly hard, and separated from all others.
- In this way, their motions were not impeded by any other surrounding bodies, nor assisted.
They then would follow the following rules.
46. Rule 1
Assume Body B and C, were perfectly equal and moving at equal speeds. B is moving from right to left, and C from left to right.

When they encountered each other, they would be reflected and then continue to move, B to the right, and C to the left, without any loss of their speed.
47. Rule 2
If B were just slightly larger than C, then only C would be reflected. Both would move to the left with the same speed.

48. Rule 3
If they were equal in mass, but B moved slightly faster than C, they would both continue moving to the left. Some of B’s excess speed would be transferred to C.

If:
- B had 6 units of speed
- C had 4 units
After the collision, each would move to the left with 5 units of speed.
49. Rule 4
Assume body C were completely at rest and slightly larger than B. No matter how fast B moved towards C, it would never move C.
Instead, it would be repelled by C in the opposite direction.

This is because a stationary body resists high velocity more than low velocity, in proportion to the excess of one over the other.
Therefore, the force in C to resist would always be greater than in B to propel.
50. Rule 5
Assume that body C were stationary and smaller than B.
No matter how slowly B moved towards C, it would move C with it, transferring a portion of its own motion to it, so that both would subsequently move at the same speed.

Specifically, if B were twice as large as C, it would transfer to C 1/3 of its motion.
This is because that 1/3 would move the body C as quickly as the remaining 2/3 would move the body B, which is twice as large.
So, after B had encountered C, it would move 1/3 slower than before. It would take the same amount of time to move through a space of 2 feet as it did before to move through a space of 3 feet.
Similarly, if B were 3 times larger than C, it would transfer to C 1/4 of its motion, and so on for the rest.
51. Rule 6
If the mass of stationary body C were precisely equal to that of the moving body B, when B approached C with 4 units of speed, it would:
- transfer 1 unit of speed to
C - be reflected with the remaining 3 units in the opposite direction.

52. Rule 7
Assume B and C were moving towards the same direction.
Cwas moving slower, withBeventually catching up to itCwere larger thanB- The speed of
Bwas greater than the excess of size inC
Then B would transfer just enough of its motion to C so that both would subsequently move at the same speed and direction.

However, if the excess of speed in B were less than the excess of size in C, then B would be reflected in the opposite direction and retain all of its motion.
These excesses are calculated as follows:
- If
Cwere twice as large asBandBdid not move twice as fast asC, it would not propelCbut would be reflected in the opposite direction. - If it moved more than twice as fast, it would propel
C.
For instance, if C had only 2 units of speed and B had 5, subtracting 2 units from B would transfer only 1 unit to C.
This would make both bodies move with 3 units of speed thereafter. This is because C is twice as large as B.
This would result in both bodies, B and C, moving with 3 units of speed.
This reasoning applies similarly to other cases.
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